T
thisnot
Guest
大家能否解释如何找到（斧| x“= 0）双锥体，其中A是一个mxn矩阵？
Navigation
Install the app
How to install the app on iOS
Follow along with the video below to see how to install our site as a web app on your home screen.
Note: This feature may not be available in some browsers.
More options
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an alternative browser.
You should upgrade or use an alternative browser.
G
Guest
Guest
[No message]
M
me2please
Guest
给定一个锥
<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$K' title="3 $亩" alt='3$K' align=absmiddle>
<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$y \in K = \{Ax|x\geq 0\}' title="3 $ ý \在K = \（斧| x \固尔奇0 \）" alt='3$y \in K = \{Ax|x\geq 0\}' align=absmiddle>对偶集
<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$K^{\ast}' title="3 $亩^（\阿斯特）" alt='3$K^{\ast}' align=absmiddle>
被定义为<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$x^{\ast} \in K^{\ast}=\{y^{T}x^{\ast}\geq 0' title="3 $χ^（\阿斯特）\在K ^（\阿斯特）= \（ý ^（Ť）χ^（\阿斯特）\固尔奇0" alt='3$x^{\ast} \in K^{\ast}=\{y^{T}x^{\ast}\geq 0' align=absmiddle>
所有
<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$y \in K \}' title="3 $ ý在K \ \）" alt='3$y \in K \}' align=absmiddle>那么<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$y^{T}x^{\ast}=(Ax)^{T}x^{\ast}=x^{T}(A^{T}x^{\ast})\geq 0' title="3 $ ý）^（Ťχ^（\阿斯特）=（AX）的^（Ť）χ^（\阿斯特）=χ^（Ť）（阿^（Ť）χ^（\阿斯特））\固尔奇0" alt='3$y^{T}x^{\ast}=(Ax)^{T}x^{\ast}=x^{T}(A^{T}x^{\ast})\geq 0' align=absmiddle>自从
<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$x \geq 0' title="3 $ x \固尔奇0" alt='3$x \geq 0' align=absmiddle>
，对偶集<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$K^{\ast}=\{A^{T}x^{\ast}\geq0\}' title="3 $亩^（\阿斯特）= \（甲）^（Ťχ^（\阿斯特）\ geq0 \）" alt='3$K^{\ast}=\{A^{T}x^{\ast}\geq0\}' align=absmiddle>这是一个多面体锥的半空间已通过原产地通过相应halfplanes有限数目（路口。）
<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$K' title="3 $亩" alt='3$K' align=absmiddle>
<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$y \in K = \{Ax|x\geq 0\}' title="3 $ ý \在K = \（斧| x \固尔奇0 \）" alt='3$y \in K = \{Ax|x\geq 0\}' align=absmiddle>对偶集
<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$K^{\ast}' title="3 $亩^（\阿斯特）" alt='3$K^{\ast}' align=absmiddle>
被定义为<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$x^{\ast} \in K^{\ast}=\{y^{T}x^{\ast}\geq 0' title="3 $χ^（\阿斯特）\在K ^（\阿斯特）= \（ý ^（Ť）χ^（\阿斯特）\固尔奇0" alt='3$x^{\ast} \in K^{\ast}=\{y^{T}x^{\ast}\geq 0' align=absmiddle>
所有
<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$y \in K \}' title="3 $ ý在K \ \）" alt='3$y \in K \}' align=absmiddle>那么<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$y^{T}x^{\ast}=(Ax)^{T}x^{\ast}=x^{T}(A^{T}x^{\ast})\geq 0' title="3 $ ý）^（Ťχ^（\阿斯特）=（AX）的^（Ť）χ^（\阿斯特）=χ^（Ť）（阿^（Ť）χ^（\阿斯特））\固尔奇0" alt='3$y^{T}x^{\ast}=(Ax)^{T}x^{\ast}=x^{T}(A^{T}x^{\ast})\geq 0' align=absmiddle>自从
<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$x \geq 0' title="3 $ x \固尔奇0" alt='3$x \geq 0' align=absmiddle>
，对偶集<img src='http://www.elektroda.pl/cgi-bin/mimetex/mimetex.cgi?3$K^{\ast}=\{A^{T}x^{\ast}\geq0\}' title="3 $亩^（\阿斯特）= \（甲）^（Ťχ^（\阿斯特）\ geq0 \）" alt='3$K^{\ast}=\{A^{T}x^{\ast}\geq0\}' align=absmiddle>这是一个多面体锥的半空间已通过原产地通过相应halfplanes有限数目（路口。）